# -*- coding: utf-8 -*- # # (c) 2019, Felix Fontein # # Ansible is free software: you can redistribute it and/or modify # it under the terms of the GNU General Public License as published by # the Free Software Foundation, either version 3 of the License, or # (at your option) any later version. # # Ansible is distributed in the hope that it will be useful, # but WITHOUT ANY WARRANTY; without even the implied warranty of # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the # GNU General Public License for more details. # # You should have received a copy of the GNU General Public License # along with Ansible. If not, see . from __future__ import absolute_import, division, print_function __metaclass__ = type import sys def binary_exp_mod(f, e, m): '''Computes f^e mod m in O(log e) multiplications modulo m.''' # Compute len_e = floor(log_2(e)) len_e = -1 x = e while x > 0: x >>= 1 len_e += 1 # Compute f**e mod m result = 1 for k in range(len_e, -1, -1): result = (result * result) % m if ((e >> k) & 1) != 0: result = (result * f) % m return result def simple_gcd(a, b): '''Compute GCD of its two inputs.''' while b != 0: a, b = b, a % b return a def quick_is_not_prime(n): '''Does some quick checks to see if we can poke a hole into the primality of n. A result of `False` does **not** mean that the number is prime; it just means that we couldn't detect quickly whether it is not prime. ''' if n <= 2: return True # The constant in the next line is the product of all primes < 200 if simple_gcd(n, 7799922041683461553249199106329813876687996789903550945093032474868511536164700810) > 1: return True # TODO: maybe do some iterations of Miller-Rabin to increase confidence # (https://en.wikipedia.org/wiki/Miller%E2%80%93Rabin_primality_test) return False python_version = (sys.version_info[0], sys.version_info[1]) if python_version >= (2, 7) or python_version >= (3, 1): # Ansible still supports Python 2.6 on remote nodes def count_bits(no): no = abs(no) if no == 0: return 0 return no.bit_length() else: # Slow, but works def count_bits(no): no = abs(no) count = 0 while no > 0: no >>= 1 count += 1 return count